1/y^2+3y+2+1/y-1=2/y^2-1

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Solution for 1/y^2+3y+2+1/y-1=2/y^2-1 equation: 



1/y^2+3y+2+1/y-1=2/y^2-1

We move all terms to the left:

1/y^2+3y+2+1/y-1-(2/y^2-1)=0



Domain of the equation: y^2!=0

y^2!=0/

y^2!=√0

y!=0

y∈R





Domain of the equation: y!=0

y∈R





Domain of the equation: y^2-1)!=0

y∈R



We add all the numbers together, and all the variables

3y+1/y^2+1/y-(2/y^2-1)+1=0

We get rid of parentheses

3y+1/y^2+1/y-2/y^2+1+1=0

We calculate fractions

We do not support eypression: y^3

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